Ep 3. Blindspots

The Purge season 2 episode 3, titled Blindspots, follows several storylines that intersect during the annual Purge night. Miguel Guerrero (Gabriel Chavarria) continues his search for his sister Penelope (Jessica Garza), who has gone missing after joining a cult known as the Matron Saints. During his quest, Miguel teams up with Pete the Cop (Dominic Fumusa), who is also looking for Penelope, as well as Rex the Realtor (Christopher Berry), who is hoping to profit from all the chaos.

Meanwhile, Jane Barbour (Amanda Warren), a high-powered executive, is holed up in her office building with a group of colleagues. However, tensions rise when it becomes clear that not everyone in the group has the same motives or loyalties. Also, in a separate storyline, a young couple named Rick (Colin Woodell) and Jenna (Hannah Anderson) get caught up in the Purge festivities when their car breaks down in a dangerous neighborhood.

As the night progresses, each character is forced to confront their own blindspots and make difficult decisions in order to survive. Miguel learns more about the Matron Saints and their enigmatic leader, Tavis (Krystal Houghton Ziv). Jane must decide whether to trust a colleague she has always disliked, and Rick and Jenna confront the harsh realities of the Purge in a way they never expected.

Blindspots is a tense and action-packed episode that showcases the strengths of the series - namely, its ability to weave together multiple storylines and explore the various facets of the Purge universe. Fans of the series will be satisfied by the continued development of Miguel and Pete's friendship, as well as Jane's growing sense of agency. Additionally, the episode introduces interesting new characters and offers tantalizing hints about the larger mythology of the Matron Saints.

Overall, Blindspots is a solid installment of The Purge that will keep viewers on the edge of their seats. Whether you are a die-hard fan of the franchise or a newcomer looking for a thrilling horror series, this episode is sure to satisfy.